3t^2+13t+7=0

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Solution for 3t^2+13t+7=0 equation: 



3t^2+13t+7=0

a = 3; b = 13; c = +7;
Δ = b2-4ac
Δ = 132-4·3·7
Δ = 85
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{85}}{2*3}=\frac{-13-\sqrt{85}}{6}
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{85}}{2*3}=\frac{-13+\sqrt{85}}{6}
$

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